$\frac{x^2-4x-20}{x+3}$
$\int\frac{-x-6}{x^2+x+6}dx$
$-4^2-4-6$
$5.4^6$
$\int5x^2\sqrt[3]{10x^3-6}dx$
$\frac{v^2+6v-16}{2v-8}+\frac{6v-30}{v-3}=\frac{v+8}{2}$
$10w^{10}-19w^9+6w^8$
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