$\int\:\:\:10\left(x+1\right)\left(x^2+2x+3\right)^4\:dx$
$r^2-8r-12$
$6a^2-18a+12=0$
$3^{x-2}=9$
$w-3w$
$3\left(a+3b\right)+\left(b-2a\right)$
$\frac{x^2-2x}{x^3-3x^2+2}$
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