$6\cdot\left(-2+2\right)$
$\frac{3x-6}{x+7}=0$
$64x^4-100y^6$
$6\cdot\:\left(3\right)^2-\left(4\right)\left(3\right)+2$
$\cos\left(\frac{3}{5}-\frac{7}{25}\right)$
$1+y'=e^y$
$-6\left(2x+1\right)=2\left(\:2x+5\right)$
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