$\frac{\sen^{2}x-5\senx+2}{\sen^{2}x-4}=\frac{2\sen-1}{\senx+2}$
$\left(3x^4+5x^3\right)\left(-8x^4+5x^3\right)$
$x^2-10x+21=0$
$-\:\left(\:-\:4\right)\:+\:3\:\left(\:11\:-\:3\right)$
$3a+7-11-9a$
$\left(8m^3n^4+5g^2d\right)^2$
$\left(-1^n\right)\frac{n+4}{n^2}$
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