$\left(2q-1\right)\left(4q-3\right)=0$
$\int7tan^2xdx$
$3\cdot\left(-1\right)^2-2\cdot\left(-1\right)-1$
$\frac{8a^2+20a-12}{a+40}$
$\lim_{x\to-1}\left(\frac{5x^2+5x}{x^2+10x+8}\right)$
$\frac{\left(x^2-2x-24\right)}{x^2-11x+30}$
$-6c+8=116$
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