$2x^3-4x^3-2x^3-5x^3$
$\left(x+12\right)^3$
$\frac{tan^{\left(2\right)}t}{sect}=sect-cost$
$\left(23b^2c^4-14d\right)^2$
$16-8+4+12-0+14$
$6x^2-13x-5$
$2\cdot3\cdot4:2\cdot4$
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