$\frac{2}{8}z^2\cdot\:\frac{2}{10}xz^4$
$8m^2+26m-24$
$\frac{3}{x+1}=\frac{3}{x-1}$
$\left(2a+4\right)^5$
$\frac{3}{4}\left(x-15\right)>2$
$g\left(x\right)=25\left(\frac{1}{625}\right)^{\left(-x-1\right)}$
$\sqrt{7}-\sqrt{7}$
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