$\lim_{x\to\frac{\pi}{2}}\left(\frac{\left(cos\left(x\right)\right)\left(1-2sin\left(x\right)\right)}{\left(2sin\left(x\right)+1\right)\left(sin\left(x\right)-1\right)}\right)$
$5b^3z^{-2}\cdot8b^{-3}z^6$
$\left(1-2cos^2x+cos^4x\right)^2$
$3y+\left(3x\right)^2\:y-2z$
$ax+y=8$
$100-64m^2$
$7x+3=4x-9$
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