$-7b\:-\:19\:-\:17b\:-\:14$
$\left(\left(3y-3x\right)^4\right)\cdot x^4$
$\int_6^8\frac{5x^2y^{-2}}{4}dx$
$\left(\frac{1}{3}x^2-\frac{1}{2}\right)^3$
$\left(mn^2+4\right)^2$
$\:\frac{2}{\left(1+x^2\right)^2}$
$y'=\frac{4y}{x}$
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