$5-x>8$
$\lim_{x\to\infty}\left(e^x+\left(\frac{2}{x}\right)\right)$
$\left(3x^3+2x-1\right)+\left(x+2\right)$
$\frac{4x}{x-1}-2\ge0$
$-\left(5+6-3\right)$
$\int\frac{4.x}{\left(x^4-x^2\right)}dx$
$\left(-8z^2\right)\left(6z^5\right)$
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