$\frac{tan\theta\:}{csc\theta\:+cot\theta\:}$
$\lim_{x\to1}\left(\frac{2x^2+5x+3}{x+1}\right)$
$\frac{m^5+2^5}{m+2}$
$\left(3a+m\right)\left(3a-m\right)$
$3n-5.38=6.62$
$\left(3ab-\frac{1}{2}c\right)^2$
$x'=te^{\left(x-t^2\right)}$
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