$\int x^2e^{\frac{1}{2}}dx$
$40^2$
$\frac{\left(x^4-2\right)^3\tan^2\left(x\right)}{\sqrt{x}\cos^2\left(x\right)}$
$x^2-4<0$
$\lim_{x\to5}\left(\frac{\sqrt{x-4}-3}{x-5}\right)$
$\frac{dy}{dx}=90yx^8$
$\frac{dy}{dx}=\frac{22}{25}$
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