$\frac{-3x^4+x^2-x+3}{x-3}$
$\:\:6\:a\:2\:\:x\:3\:\:+\:9\:a\:b\:x\:2\:\:+3\:a\:c\:x\:2$
$y'\:=\:\:\frac{y}{x}-1$
$3m^3n^2-12n^3m^2-7m^3$
$4m^n^2\:+\:25h^2n^2\:+\:4m^2\:+\:25h^2$
$\frac{dy}{du}-e^{-2u+3y}=0$
$3ab-5bc$
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