$4 x ^ { 2 } - 8 x ^ { 4 } - 6 x ^ { 3 } + 2 x ^ { 2 } - 6 x + 10$

$\int\left(\frac{1+\cot^2x}{\cot^2x}\right)dx$

$\ln\sqrt{t}+1$

$-15\:-9\:+\:2\:+\:-\:13$

$\left(y-7\right)\left(y-3\right)$

$\frac{\left(4x^4+3x^3+11x^2\right)}{\left(x+4\right)}$

$\frac{1}{2x}+\frac{1}{4}=\frac{1}{10x}+\frac{1}{5}$