$0,04x^2-0,16z^2$

$\lim_{x\to\infty}\left(\frac{x^3+2x^2+5x^5}{2x^4+4x^5}\right)$

$4\cdot2\cdot18$

$sin\theta\:\left(csc\theta\:-sin\theta\:\right)$

$b=\frac{\cos\left(x\right)+\sin\left(x\right)\cdot\tan\left(x\right)}{\sin\left(x\right)\cdot\sin\left(x\right)}$

$\frac{sec\left(u\right)}{\sec\left(u\right)-1}=\frac{1}{1-cos\left(u\right)}$

$1-216$