$\sqrt[5]{10^4x}$
$x^4-4$
$\left(2x^2+5x+3\right)entre\left(x-1\right)$
$\frac{y^3-1}{y-1}$
$\lim_{n\to\infty}\:2^n$
$5x^2+22x+1,2$
$\sqrt{6+\sqrt{4+\sqrt{x+2}}}=1$
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