$\lim_{x\to0}\left(\frac{1}{\sin\left(8\right)}\cos\left(7\right)\right)$
$\frac{dy}{dx}=x\left(y^3\right)$
$4x^2+23x+33=2x+8$
$\frac{dy}{dx}=9+\sqrt{y-2x+9}$
$4x-6\le2$
$\left(2x-3\right)^2-3x^2>11-11x$
$-2\:+\:\left(3\:-\:2\right)\:-\:\left[\left(4\:-\:3\right)\:-\:\left(-2\right)\right]$
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