$\frac{3x^3+6x^2-10x+2}{x+1}$
$\left(-7\right)\left(-21\right)\left(23\right)\left(-5\right)\left(3\right)$
$8\cdot3.16$
$4x^4+8x^2+4$
$5-6+1-8-2+6+4$
$\frac{d}{dx}2y^2-x^2+x^3y$
$\lim_{x\to\infty}\left(\frac{2x^3-4x}{x^3-3x+5}\right)$
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