$y'=\frac{5y}{x+4}$
$x+6>4-3x$
$\int r^4\left(7-\frac{r^5}{10}\right)^3dr$
$3^3+t^3$
$2b+4d$
$\int\left(6x^2-3\right)^5x\:dx$
$y=\frac{2}{3}x-1$
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