$7-\left(8+5-3\right)+\left(-2-4\right)$
$\lim_{x\to0}\left(\frac{tan8x}{sin4x}\right)$
$-1:-1$
$\frac{1-x}{-2\:}<2x$
$\frac{x^3-64}{x-8}$
$\frac{dy}{dx}\left(6x^3y^2-3x^2y=4\right)$
$\frac{s^3+s^2+s+2}{\left(s^2+1\right)\left(s^2+1\right)}$
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