$16x^4+4y^2+4$
$x=3x^2$
$200\cdot\left(-3\right)$
$y\left(x\right)=y'\left(x\right)\left(x+\:y'\left(x\right)+1\right)$
$\frac{dy}{dx}=\frac{x+y+4}{2x+2y-1}$
$y'=\frac{\left(y-22\right)}{\left(x-2\right)}$
$p^2-1+9q^2-6pq$
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