$\lim_{x\to4}\left(4x^2-5x+1\right)$
$-4x+6+3x^2-1-2x$
$\int\frac{8x^2}{\left(4-x^3\right)^4}dx$
$3x+6y=9$
$\frac{11^{-2}}{11^{-2}}$
$\left(-2-2y\right)^2$
$\frac{\left(t+1\right)}{t}=\frac{1}{t}$
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