$3x-1<x+12$
$\frac{8^9}{8^7}$
$x^2-8x-24=0$
$3x+1\le5x+7$
$8vu^3\cdot4u^2v^4$
$\int_0^7\left(te^{-t}\right)dt$
$2x+3y+2y-3+5x-y+8$
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