$y'-9y=0$
$1x^2-10x+25$
$-2x+8\left(5+x\right)-5$
$\lim_{x\to-5}\left(x^2-25\right)\lim_{x\to-5}\left(x+5\right)$
$\frac{d}{dx}u^4$
$\left(2x-19\right)\left(2x\:+10\right)$
$-x+5y=19$
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