$y+1=4x^2-2xy$
$\lim_{x\to\infty}\left(\frac{8}{6^x}\right)$
$13,54-7,45$
$\int\frac{ln\left(8x\right)}{x^4}dx$
$\left(8y\:+\:10x\right)dx\:+\:\left(5y\:+\:7x\right)dy\:=\:0$
$\int\frac{\left(\sqrt{x^2+4}\right)}{y}dx$
$=\frac{21-x-2x}{xp}$
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