$\left(\:\frac{2}{5}x^5+\frac{5}{3}\:y\right)^2$
$\frac{8^3-y^3}{2x-y}$
$tan\left(3\pi+x\right)=tanx$
$0\cdot24\left(-1\cdot1\right)$
$-n+4\left(4n+1\right)$
$\frac{\left(1\:-\:a\:-\:a^5\:-\:3a\:^2\right)}{\left(1\:+\:2a\:+\:a^2\right)}$
$5p-9=2p+12$
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