$ln\left(4x+8\right)^4$
$-\frac{1}{4}x^2y^2+\frac{7}{8}x+8x^4+\frac{3}{8}x^2y^2-9x^4$
$m+4=32$
$\lim_{x\to0}\left(4x\right)^{\left(x^8\right)}$
$6a^2b^3+4ab^2-2a^3b$
$x^3\sqrt{x^2}$
$24\:+\:s\:=\:47$
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