$3\cdot3-1$
$\frac{dy}{dx}=\frac{x}{9y}$
$\int\left(x\left(x^2-9\right)^5\right)dx$
$\left(4mn\right)\left(-15mn\right)$
$\left(2x^2-5x+6\right)\left(2x^4-5x^3-6x^2+4x-3\right)$
$3^3+6^2+2$
$1+\sqrt{2}+x=\sqrt{7}+y$
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