$112x^3-175x$
$3x^2\:-\:27x\:+\:42$
$\sqrt[3]{a^{7}b^{12}}$
$\frac{7x-2x^3-5}{x+2}$
$\frac{x^6y^2z^5}{x^{-3}y^{-9}z^2}$
$\left(1+\tan\left(b\right)+\sec\left(b\right)\right)\cdot\left(1+\cot\left(b\right)-\csc\left(b\right)\right)$
$3^{5x-8}=9^{2x+4}$
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