$\left(3a+2\right)^2-\left(3a-2\right)^2$
$4\left(5\right)\cdot8\left(2\right)$
$\frac{7}{-6-x}$
$8^0+6^0-17^1$
$46-\left(38-\left(-2\right)+-9+\left(42-18+15\right)-\left(-7\right)$
$\frac{4x}{3}-\frac{5}{9}=\frac{7}{9}$
$\left(-0\right)+\left(-346\right)$
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