$\frac{x^4+3x^39x-1}{x-1}$
$4^{x+3}=\left(\frac{1}{2}\right)^x$
$\frac{x^{15}-64}{x^5-4}$
$\frac{\tan\left(x\right)+1}{\sec\left(x\right)+\cot\left(x\right)}$
$-8\cdot2-\left(-14\right)$
$a^3-a^2+a-1;\:a=-2;\:b=-3$
$tan\:cot\:=1$
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