$\frac{x^4-x^3+x^2-3x-6}{x+3}$
$-\left(x-c\right)\left(x+7\right)$
$2\left(1+\cos\left(x\right)\right)$
$3e^3+25e^2+36e+36$
$3x+7-2x-5$
$\frac{a+1^3}{a+1}.$
$\lim_{x\to\infty}\left(1+\frac{3}{x+1}\right)^{3x+1}$
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