$\lim_{x\to2}\frac{\left(x-2\right)^2}{x^2-16}$
$\frac{\sin\left(4x\right)}{\sin\left(x\right)}=4\cos$
$\frac { 4 } { \frac { 1 } { 3 } }$
$x^2+x-42=0$
$3x^2+3y^2-2y^2+2x^2-3x^2y^2$
$\left(m-2\right)\left(m-3\right)$
$3x+25,25>2x+30,45$
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