$\left(d^9\right)^3$
$\frac{\sqrt{x}}{\sqrt{x}-1}$
$\sqrt{4\cdot25}$
$\lim_{x\to2}\left(\frac{4x^2-16}{x^2-4}\right)$
$0.25x^2-10x+800$
$3.6-b=-3.9$
$\frac{d}{dx}\frac{e^x}{5x+4}$
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