$\left(3x+2\right)^2-\left(2x+3\right)^2$
$\lim_{x\to\infty}\frac{3x^3+4x^2-5}{2x^2-3x+6}$
$\lim_{x\to-\infty}\left(5e^{0.07x}-8.2\right)$
$\frac{d^2}{dx^2}\left(x\left(2x+1\right)^3\right)$
$\left(\frac{2}{3}x^2+\frac{1}{4}y^3\right)^'^2$
$\lim_{x\to\infty}\:\left(e\left(\sqrt[-x]{x}\right)\right)$
$\frac{1-\sin^2\left(x\right)}{\cos\left(x\right)+\sin\left(x\right)\cos\left(x\right)}=\frac{1-\sin\left(x\right)}{\cos\left(x\right)}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!