$x^3+6x^2-13x-42$
$\frac{8x}{\tan\left(7x\right)}$
$\frac{3x-2}{4}>\frac{2\left(x-1\right)}{6}$
$6\sin\left(a\right)-3=0$
$3x^2-18x+6$
$a^{x+1}\cdot a$
$8-\left(1-12\right)-\left\{\left(-6\right)-4\right\}$
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