$12x+11^2$
$\left(2x+y+52\right)^2$
$x^2+52x+169$
$3\le x$
$arccos\left(16x\right)=arcsec\left(x\right)$
$\frac{\frac{\sin^2\left(x\right)}{\cos^2\left(x\right)}}{\frac{\sin^2\left(x\right)}{\cos^2\left(x\right)}}$
$6t^5\left(t^4-2t\right)$
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