$\left(\frac{21a^2b^4-6a^5+7ab^3}{7ab^3}\right)$
$\frac{d}{dx}e^y=y^3+x^{\frac{2}{3}}$
$3^0+9$
$4c^2-12c+9$
$g\:\left(x\right)=\left(x\:-2\right)\left(3x\:+3\right)$
$4\left(2\sqrt{3}\right)$
$-\frac{36}{\left(-17+2\cdot4\right)}$
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