$\frac{d}{dx}\left(y=\:ln3x\:sec^2\:\frac{x}{2}\:tan3x\right)$
$45+28+103$
$12cos^2x-9=0$
$9a^2-12az+4z^2$
$\lim_{x\to0}\left(\arcsec\left(\frac{\left(4-4\cos\left(x\right)\right)}{\sqrt{3}x^2}\right)\right)$
$\int\left(9x+9\right)^{2.4}dx$
$2n^4\cdot4n$
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