$\frac{1}{2}\left(\frac{5}{n}+1\right)$
$\ln\left(\tan\left(3x\right)^3\right)$
$\left(3a-5b+3c\right)-\left(4a-3b+2c\right)$
$5+1+100+1+5$
$\lim_{x\to\infty}7$
$-58\left(-15\right)$
$732+\left(-485\right)$
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