$\lim_{x\to2}\left(\frac{\sqrt{3x}}{x\sqrt{x+1}}\right)$
$\frac{x^2-x-6}{x-5}$
$x^2\:-\:2x\:-\:24\:\ge\:0$
$\frac{8x^9+y^6}{2x^3+y^2}$
$m+5>10$
$\frac{\left(x^3-10x-12\right)}{x+2}$
$x^3+3x-2y+4x^3$
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