$9\cos^2\left(x\right)-3\cos\left(x\right)-5=0$
$\left(-12\right)+\left(+4\right)+\left(+1\right)$
$\lim_{x\to0}\left(\frac{\cos\left(4x\right)-1}{x\tan\left(3x\right)}\right)$
$\int\frac{7x+3}{x^2+3x+4}dx$
$45\cdot99$
$96+80-52+46+76-62$
$\left(3x-y\right)\left(9x^2+3xy+y^2\right)$
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