$10x^5+7=40x+7$
$-x-9+3x$
$2\cdot\log_{11}\left(x+3\right)=\log_{11}\left(6x+11\right)$
$x+3y-4z=-4$
$3x+y=46$
$6\:+\:\:4\:-\:\left[\:17\:-\:\left(\:4\:.\:4\:\right)\:\right]\:+\:3\:\:-\:5$
$6x^5+30x^4+12x^3$
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