$\int\frac{x-\:12}{x^2+x-6}dx$
$3^3.3^3.3$
$\int_1^3\left(\frac{3c}{2}\right)-\left(\frac{cx}{2}\right)dx$
$2x\frac{dy}{dx}+5xy=0$
$x^2-19x-92$
$\sec\left(x\right)^2+4=\tan^2\left(x\right)+5$
$-18x^3-9x^3-6$
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