$\frac{5x}{3}+\frac{3}{2}>\frac{1}{6}-\frac{4x}{3}$
$\left(3a^7\right)\left(2a^5\right)$
$\int\frac{x-1}{3x^2-6x+2}dx$
$4\int_1^{\infty}\left(\frac{1}{x\sqrt{2x^2-1}}\right)dx$
$\left(\sqrt[3]{5+\sqrt[3]{12+3\cdot\sqrt{5\cdot\left(2+\sqrt{9}\right)}}}\right)$
$3.5\cdot10^4+7.2\cdot10^5$
$x^2-6x=86$
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