$\left(1\right)^3+3\left(1\right)^2+2\left(1\right)$
$\frac{2xy}{4y}$
$\frac{dx}{dt}+\frac{4x}{t}=t^2-1$
$\sqrt{121x^{2a}y^{4b}}$
$+32+45+69-15$
$\frac{\sin\left(6x\right)}{\sin\left(3x\right)}-\frac{\cos\left(6x\right)}{\cos\left(3x\right)}=\sec\left(3x\right)$
$x^2-7x+10;\:x=1$
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