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# Rationalize the denominator $\frac{\left(\sqrt{2}\sqrt{13+\sqrt{7}}-2\sqrt{5-\sqrt{7}}\right)\cdot 1}{\sqrt{3-\sqrt{7}}}$

## Step-by-step Solution

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###  Videos

$3\sqrt{2}$
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##  Step-by-step Solution 

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Calculate the square root of $7$

$\frac{\left(\sqrt{2}\sqrt{13+\sqrt{7}}-2\sqrt{5-\sqrt{7}}\right)\cdot 1}{\sqrt{3-\sqrt{7}}}$

Learn how to solve rationalisation problems step by step online.

$\frac{\left(\sqrt{2}\sqrt{13+\sqrt{7}}-2\sqrt{5-\sqrt{7}}\right)\cdot 1}{\sqrt{3-\sqrt{7}}}$

Learn how to solve rationalisation problems step by step online. Rationalize the denominator ((2^1/2(13+7^1/2)^1/2-2(5-7^1/2)^1/2)1)/((3-7^1/2)^1/2). Calculate the square root of 7. Calculate the square root of 2. Calculate the square root of 7. Calculate the square root of 7.

$3\sqrt{2}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Rationalisation

In elementary algebra, root rationalisation is a process by which radicals in the denominator of an algebraic fraction are eliminated.

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