$6\left(5n\right)$
$\left(\frac{b}{3}^2\right)$
$\left(x+5\right)^2+\left(x+7\right)^2=16$
$3\left(3x+2\right)+2x-5=3+10x$
$\frac{dy}{dx}=6x^5y$
$\left(+7\right)\left(-8\right)+\left(-5\right)\left(-9\right)-\left(+8\right)\left(-9\right)$
$\frac{2a^3b^5}{3}\cdot\frac{-7a^2b}{4}$
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