$\frac{d}{dx}\left(y^2-x^2=\tan2x\right)$
$\int_0^{10}\left(a\right)dx$
$\frac{-6n^8}{-2n}$
$cos\:15=\frac{\sqrt{a}\left(\sqrt{b}+1\right)}{4}$
$\frac{dy}{dx}=\frac{3y^2}{x+2}$
$4^{-2}\cdot4^5$
$x\left(y-3\right)y'=5y$
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