$-x^2\leq 0$
$64x^4-81$
$4x^2\:+\:20x\:+\:25\:=\:1$
$\frac{3x^6}{4x^2}$
$x\frac{dy}{dx}=\left(1+y^2\right)$
$\frac{x+1}{2x-1}=\frac{3}{4x-1}$
$\left(2x+\frac{2}{3}\right)^2$
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